Fractional programming

Let ${\displaystyle f,g,h_{j},j=1,\ldots ,m}$ be real-valued functions defined on a set ${\displaystyle \mathbf {S} _{0}\subset \mathbb {R} ^{n}}$. Let ${\displaystyle \mathbf {S} =\{{\boldsymbol {x}}\in \mathbf {S} _{0}:h_{j}({\boldsymbol {x}})\leq 0,j=1,\ldots ,m\}}$. The nonlinear program

${\displaystyle {\underset {{\boldsymbol {x}}\in \mathbf {S} }{\text{maximize}}}\quad {\frac {f({\boldsymbol {x}})}{g({\boldsymbol {x}})}},}$

where ${\displaystyle g({\boldsymbol {x}})>0}$ on ${\displaystyle \mathbf {S} }$, is called a fractional program.

A fractional program in which f is nonnegative and concave, g is positive and convex, and S is a convex set is called a concave fractional program. If g is affine, f does not have to be restricted in sign. The linear fractional program is a special case of a concave fractional program where all functions ${\displaystyle f,g,h_{j},j=1,\ldots ,m}$ are affine.

The function ${\displaystyle q({\boldsymbol {x}})=f({\boldsymbol {x}})/g({\boldsymbol {x}})}$ is semistrictly quasiconcave on S. If f and g are differentiable, then q is pseudoconcave. In a linear fractional program, the objective function is pseudolinear.

By the transformation ${\displaystyle {\boldsymbol {y}}={\frac {\boldsymbol {x}}{g({\boldsymbol {x}})}};t={\frac {1}{g({\boldsymbol {x}})}}}$, any concave fractional program can be transformed to the equivalent parameter-free concave program^[1]

${\displaystyle {\begin{aligned}{\underset {{\frac {\boldsymbol {y}}{t}}\in \mathbf {S} _{0}}{\text{maximize}}}\quad &tf\left({\frac {\boldsymbol {y}}{t}}\right)\\{\text{subject to}}\quad &tg\left({\frac {\boldsymbol {y}}{t}}\right)\leq 1,\\&t\geq 0.\end{aligned}}}$

If g is affine, the first constraint is changed to ${\displaystyle tg({\frac {\boldsymbol {y}}{t}})=1}$ and the assumption that g is positive may be dropped. Also, it simplifies to ${\displaystyle g({\boldsymbol {y}})=1}$.

The Lagrangian dual of the equivalent concave program is

${\displaystyle {\begin{aligned}{\underset {\boldsymbol {u}}{\text{minimize}}}\quad &{\underset {{\boldsymbol {x}}\in \mathbf {S} _{0}}{\operatorname {sup} }}{\frac {f({\boldsymbol {x}})-{\boldsymbol {u}}^{T}{\boldsymbol {h}}({\boldsymbol {x}})}{g({\boldsymbol {x}})}}\\{\text{subject to}}\quad &u_{i}\geq 0,\quad i=1,\dots ,m.\end{aligned}}}$