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1918 Nebraska gubernatorial election
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1918 Nebraska gubernatorial election

1918 Nebraska gubernatorial election

← 1916 November 5, 1918 1920 →
 
Nominee Samuel R. McKelvie Keith Neville
Party Republican Democratic
Popular vote 120,888 97,886
Percentage 54.4% 44.1%

County results
McKelvie:      40–50%      50–60%      60–70%      70–80%
Neville:      40–50%      50–60%      60–70%      70–80%

Governor before election

Keith Neville
Democratic

Elected Governor

Samuel R. McKelvie
Republican

The 1918 Nebraska gubernatorial election was held on November 5, 1918, and featured former lieutenant governor Samuel R. McKelvie, a Republican, defeating incumbent Democratic governor, Keith Neville.

Democratic primary

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Candidates

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Results

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Democratic primary results[1]
Party Candidate Votes %
Democratic Keith Neville 38,629 62.13
Democratic Charles W. Bryan 23,548 37.87

Prohibition primary

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Candidates

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Results

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Prohibition primary results[1]
Party Candidate Votes %
Prohibition Julian D. Graves 172 93.99
Prohibition Charles W. Bryan 11 6.01

Republican primary

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Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican Samuel R. McKelvie 46,375 71.70
Republican Walter Johnson 18,308 28.30

General election

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Results

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Nebraska gubernatorial election, 1918[3]
Party Candidate Votes %
Republican Samuel R. McKelvie 120,888 54.41%
Democratic Keith Neville (incumbent) 97,886 44.06%
Prohibition Julian D. Graves 3,409 1.53%
Total votes 222,183 100.0%
Republican gain from Democratic

See also

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References

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