Lake Harbor is a census-designated place (CDP) in Palm Beach County, Florida, United States. It is part of the Miami metropolitan area of South Florida despite being physically and culturally closer to the Florida Heartland. The population was 49 at the 2020 US census.

Lake Harbor is located at 26°41′13″N 80°48′27″W / 26.68694°N 80.80750°W / 26.68694; -80.80750 (26.686985, -80.807613).

According to the United States Census Bureau, the CDP has a total area of 3.4 km² (1.3 sq mi), all land. The community is centered at the intersection of Mutt Thomas Road and U.S. Route 27 (which runs concurrently with Florida State Road 80).

It is located along the southern banks of Lake Okeechobee, at the beginning of the Miami Canal. John Stretch Park is also located alongside the north end of Lake Harbor and the Lake Okeechobee.

As of the 2020 United States census, there were 49 people, 15 households, and 15 families residing in the CDP.

As of the 2020 United States census, there were 45 people, 0 households, and 0 families residing in the CDP.

As of the census of 2000, there were 195 people, 65 households, and 44 families residing in the CDP. The population density was 57.5 people/km² (149 people/sq mi). There were 118 housing units at an average density of 34.8 units/km² (90 units/sq mi). The racial makeup of the CDP was 41.54% White (35.9% were Non-Hispanic White), 42.56% African American, 3.08% Asian, 2.05% from other races, and 10.77% from two or more races. Hispanic or Latino of any race were 6.67% of the population.

In 2000, there were 65 households, out of which 32.3% had children under the age of 18 living with them, 50.8% were married couples living together, 12.3% had a female householder with no husband present, and 32.3% were non-families. 24.6% of all households were made up of individuals, and 4.6% had someone living alone who was 65 years of age or older. The average household size was 3.00 and the average family size was 3.55.