Absolute presentation of a group

To define an absolute presentation of a group ${\displaystyle G}$ one specifies a set ${\displaystyle S}$ of generators and sets ${\displaystyle R}$ and ${\displaystyle I}$ of relations and irrelations among those generators. We then say ${\displaystyle G}$ has absolute presentation

${\displaystyle \langle S\mid R,I\rangle }$

provided that:

1. ${\displaystyle G}$ has presentation ${\displaystyle \langle S\mid R\rangle .}$
2. Given any homomorphism ${\displaystyle h:G\rightarrow H}$ such that the irrelations ${\displaystyle I}$ are satisfied in ${\displaystyle h(G)}$, ${\displaystyle G}$ is isomorphic to ${\displaystyle h(G)}$.

A more algebraic, but equivalent, way of stating condition 2 is:

2a. If ${\displaystyle N\triangleleft G}$ is a non-trivial normal subgroup of ${\displaystyle G}$ then ${\displaystyle I\cap N\neq \left\{1\right\}.}$

Remark: The concept of an absolute presentation has been fruitful in fields such as algebraically closed groups and the Grigorchuk topology. In the literature, in a context where absolute presentations are being discussed, a presentation (in the usual sense of the word) is sometimes referred to as a relative presentation, which is an instance of a retronym.

The cyclic group of order 8 has the presentation

${\displaystyle \langle a\mid a^{8}=1\rangle .}$

But, up to isomorphism there are three more groups that "satisfy" the relation ${\displaystyle a^{8}=1,}$ namely:

${\displaystyle \langle a\mid a^{4}=1\rangle }$

${\displaystyle \langle a\mid a^{2}=1\rangle }$ and

${\displaystyle \langle a\mid a=1\rangle .}$

However, none of these satisfy the irrelation ${\displaystyle a^{4}\neq 1}$. So an absolute presentation for the cyclic group of order 8 is:

${\displaystyle \langle a\mid a^{8}=1,a^{4}\neq 1\rangle .}$

It is part of the definition of an absolute presentation that the irrelations are not satisfied in any proper homomorphic image of the group. Therefore:

${\displaystyle \langle a\mid a^{8}=1,a^{2}\neq 1\rangle }$

Is not an absolute presentation for the cyclic group of order 8 because the irrelation ${\displaystyle a^{2}\neq 1}$ is satisfied in the cyclic group of order 4.

The notion of an absolute presentation arises from Bernhard Neumann's study of the isomorphism problem for algebraically closed groups.^[1]

A common strategy for considering whether two groups ${\displaystyle G}$ and ${\displaystyle H}$ are isomorphic is to consider whether a presentation for one might be transformed into a presentation for the other. However algebraically closed groups are neither finitely generated nor recursively presented and so it is impossible to compare their presentations. Neumann considered the following alternative strategy:

Suppose we know that a group ${\displaystyle G}$ with finite presentation ${\displaystyle G=\langle x_{1},x_{2}\mid R\rangle }$ can be embedded in the algebraically closed group ${\displaystyle G^{*}}$ then given another algebraically closed group ${\displaystyle H^{*}}$, we can ask "Can ${\displaystyle G}$ be embedded in ${\displaystyle H^{*}}$?"

It soon becomes apparent that a presentation for a group does not contain enough information to make this decision for while there may be a homomorphism ${\displaystyle h:G\rightarrow H^{*}}$, this homomorphism need not be an embedding. What is needed is a specification for ${\displaystyle G^{*}}$ that "forces" any homomorphism preserving that specification to be an embedding. An absolute presentation does precisely this.

• Presentation of a group