Recent from talks
Nothing was collected or created yet.
Half-reaction
View on WikipediaIn chemistry, a half reaction (or half-cell reaction) is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction. Often, the concept of half reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).
Half reactions are often used as a method of balancing redox reactions. For oxidation-reduction reactions in acidic conditions, after balancing the atoms and oxidation numbers, one will need to add H+ ions to balance the hydrogen ions in the half reaction. For oxidation-reduction reactions in basic conditions, after balancing the atoms and oxidation numbers, first treat it as an acidic solution and then add OH− ions to balance the H+ ions in the half reactions (which would give H2O).
Example: Zn and Cu galvanic cell
[edit]
Consider the Galvanic cell shown in the adjacent image: it is constructed with a piece of zinc (Zn) submerged in a solution of zinc sulfate (ZnSO4) and a piece of copper (Cu) submerged in a solution of copper(II) sulfate (CuSO4). The overall reaction is:
- Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s)
At the Zn anode, oxidation takes place (the metal loses electrons). This is represented in the following oxidation half reaction (note that the electrons are on the products side):
- Zn(s) → Zn2+ + 2 e−
At the Cu cathode, reduction takes place (electrons are accepted). This is represented in the following reduction half reaction (note that the electrons are on the reactants side):
- Cu2+ + 2 e− → Cu(s)
Example: oxidation of magnesium
[edit]
Consider the example burning of magnesium ribbon (Mg). When magnesium burns, it combines with oxygen (O2) from the air to form magnesium oxide (MgO) according to the following equation:
- 2 Mg(s) + O2(g) → 2 MgO(s)
Magnesium oxide is an ionic compound containing Mg2+ and O2− ions whereas Mg(s) and O2(g) are elements with no charges. The Mg(s) with zero charge gains a +2 charge going from the reactant side to product side, and the O2(g) with zero charge gains a −2 charge. This is because when Mg(s) becomes Mg2+, it loses 2 electrons. Since there are 2 Mg on left side, a total of 4 electrons are lost according to the following oxidation half reaction:
- 2 Mg(s) → 2 Mg2+ + 4 e−
On the other hand, O2 was reduced: its oxidation state goes from 0 to −2. Thus, a reduction half reaction can be written for the O2 as it gains 4 electrons:
- O2(g) + 4 e− → 2 O2−
The overall reaction is the sum of both half reactions:
- 2 Mg(s) + O2(g) + 4 e− → 2 Mg2+ + 2 O2− + 4 e−
When chemical reaction, especially, redox reaction takes place, we do not see the electrons as they appear and disappear during the course of the reaction. What we see is the reactants (starting material) and end products. Due to this, electrons appearing on both sides of the equation are canceled. After canceling, the equation is re-written as
- 2 Mg(s) + O2(g) → 2 Mg2+ + 2 O2−
Two ions, positive (Mg2+) and negative (O2−) exist on product side and they combine immediately to form a compound magnesium oxide (MgO) due to their opposite charges (electrostatic attraction). In any given oxidation-reduction reaction, there are two half reactions—oxidation half reaction and reduction half reaction. The sum of these two half reactions is the oxidation–reduction reaction.
Half-reaction balancing method
[edit]Consider the reaction below:
- Cl2 + 2 Fe2+ → 2 Cl− + 2 Fe3+
The two elements involved, iron and chlorine, each change oxidation state; iron from +2 to +3, chlorine from 0 to −1. There are then effectively two half reactions occurring. These changes can be represented in formulas by inserting appropriate electrons into each half reaction:
- Fe2+ → Fe3+ + e−
- Cl2 + 2 e− → 2 Cl−
Given two half reactions it is possible, with knowledge of appropriate electrode potentials, to arrive at the complete (original) reaction the same way. The decomposition of a reaction into half reactions is key to understanding a variety of chemical processes. For example, in the above reaction, it can be shown that this is a redox reaction in which Fe is oxidised, and Cl is reduced. Note the transfer of electrons from Fe to Cl. Decomposition is also a way to simplify the balancing of a chemical equation. A chemist can atom balance and charge balance one piece of an equation at a time.
For example:
- Fe2+ → Fe3+ + e− becomes 2 Fe2+ → 2 Fe3+ + 2e−
- is added to Cl2 + 2 e− → 2 Cl−
- and finally becomes Cl2 + 2 Fe2+ → 2 Cl− + 2 Fe3+
It is also possible and sometimes necessary to consider a half reaction in either basic or acidic conditions, as there may be an acidic or basic electrolyte in the redox reaction. Due to this electrolyte it may be more difficult to satisfy the balance of both the atoms and charges. This is done by adding H2O, OH−, e−, and/or H+ to either side of the reaction until both atoms and charges are balanced.
Consider the half reaction below:
- PbO2 → PbO
OH−, H2O, and e− can be used to balance the charges and atoms in basic conditions, as long as it is assumed that the reaction is in water.
- 2 e− + H2O + PbO2 → PbO + 2 OH−
Again consider the half reaction below:
- PbO2 → PbO
H+, H2O, and e− can be used to balance the charges and atoms in acidic conditions, as long as it is assumed that the reaction is in water.
- 2 e− + 2 H+ + PbO2 → PbO + H2O
Notice that both sides are both charge balanced and atom balanced.
Often there will be both H+ and OH− present in acidic and basic conditions but that the resulting reaction of the two ions will yield water.
- H+ + OH− → H2O
See also
[edit]References
[edit]Half-reaction
View on GrokipediaFundamentals
Definition
A half-reaction represents either the oxidation or reduction component of a complete redox reaction, obtained by isolating the changes in oxidation states and balancing the equation with electrons to account for charge differences.[4] This approach simplifies the analysis of redox processes by decoupling the electron transfer mechanisms that occur simultaneously in the full reaction, allowing chemists to study each part independently, particularly in electrochemical contexts.[4] In an oxidation half-reaction, electrons are lost as the oxidation state of the species increases, with the reducing agent serving as the electron donor.[4] Conversely, a reduction half-reaction involves the gain of electrons, decreasing the oxidation state, where the oxidizing agent accepts the electrons.[4] These distinctions highlight the complementary nature of the two half-reactions, which together form a balanced redox pair without net electron accumulation.[5] Half-reactions are conventionally notated using standard chemical equation formats, with reactants on the left and products on the right separated by an arrow indicating direction.[6] For oxidation, electrons appear as products (e.g., reactant → product + e⁻), while for reduction, they are reactants (e.g., reactant + e⁻ → product), ensuring charge balance in each isolated equation.[4] The conceptual foundations of half-reactions trace to 18th-century advancements in understanding redox processes, pioneered by Antoine Lavoisier, who reframed combustion and corrosion as oxidation reactions involving oxygen rather than the release of phlogiston.[7] Lavoisier's work in the 1770s and 1780s established the dualistic view of oxidation and reduction, laying the groundwork for later electrochemical interpretations that formalized these as separable half-reactions.[8]Role in Redox Processes
Half-reactions serve as the fundamental building blocks of redox processes, isolating the oxidation and reduction components of a complete reaction. The oxidation half-reaction depicts the loss of electrons by a species, while the reduction half-reaction shows the gain of electrons by another. To form the overall redox reaction, these half-reactions are combined by multiplying them to equalize the number of electrons transferred, then adding them together, with the electrons canceling out. This approach simplifies the analysis of complex reactions by allowing chemists to examine each process independently before integration.[4] In electrochemical systems, half-reactions are essential for understanding and predicting the behavior of voltaic cells, where the oxidation half-reaction occurs at the anode and the reduction half-reaction at the cathode. The standard cell potential, , is calculated as , using tabulated standard reduction potentials () for each half-reaction. A positive indicates a spontaneous reaction, enabling the design and optimization of devices like batteries. This method allows initial assessment of reaction feasibility without deriving the full coupled equation.[9] Standard half-reaction potentials are referenced to the standard hydrogen electrode (SHE), defined by the half-reaction with at 25°C. These values are tabulated for common species, such as at +0.337 V, facilitating comparisons and predictions across diverse systems.[9] Half-reactions are particularly valuable in analyzing processes like corrosion, where the anodic oxidation of a metal (e.g., ) couples with a cathodic reduction (e.g., oxygen or hydrogen evolution), without immediately requiring the complete equation. Similarly, in batteries, they underpin the evaluation of energy storage and discharge mechanisms, aiding in the development of efficient electrochemical technologies.[10]Examples
Zinc-Copper Galvanic Cell
The Daniell cell, a prototypical galvanic cell, features a zinc anode immersed in a zinc sulfate (ZnSO₄) solution and a copper cathode immersed in a copper(II) sulfate (CuSO₄) solution, with the two half-cells separated by a porous barrier or salt bridge to prevent direct mixing while allowing ion migration.[11][12] At the zinc anode, oxidation occurs according to the half-reaction:This process releases electrons that flow through the external circuit toward the copper electrode.[13][12] At the copper cathode, reduction takes place via the half-reaction:
Here, copper(II) ions in solution accept the electrons to deposit as copper metal on the electrode.[13][12] The overall cell reaction combines these half-reactions:
Under standard conditions, the cell potential is calculated as , indicating a spontaneous redox process that generates electrical energy.[14][15][16]
Magnesium Oxidation
Magnesium demonstrates significant reactivity in aqueous environments, undergoing oxidation when reacting with water or acids to liberate hydrogen gas. In acidic conditions, such as with hydrochloric acid, magnesium metal displaces hydrogen ions, resulting in a complete redox process where magnesium is oxidized and protons are reduced. This reaction is notably vigorous, producing effervescence due to the rapid evolution of hydrogen gas bubbles, and is exothermic, releasing heat that can cause the solution temperature to rise appreciably.[17][18] The oxidation half-reaction for magnesium is represented as: This process involves the loss of two electrons per magnesium atom, converting the neutral metal to the divalent cation in solution. For contextual completeness in acidic media, the corresponding reduction half-reaction is: However, the focus remains on the oxidation of magnesium, which drives the overall reactivity observed. With water alone, the reaction proceeds more slowly, particularly at room temperature, forming magnesium hydroxide and hydrogen gas, but accelerates under heated conditions.[19][20][21] Beyond laboratory demonstrations, the oxidative behavior of magnesium finds practical application in corrosion prevention through sacrificial anodes. In this method, magnesium, being more reactive than metals like iron or steel, is connected to the protected structure, preferentially oxidizing and thereby cathodically protecting the less active metal from corrosion in environments such as soil or seawater. This sacrificial role extends the lifespan of pipelines, ship hulls, and underground infrastructure by continuously supplying electrons to inhibit anodic dissolution of the primary material.[22][23]Balancing Procedures
Acidic Conditions
Balancing half-reactions in acidic conditions follows a systematic procedure that accounts for the availability of hydrogen ions (H⁺) in the medium, ensuring conservation of both mass and charge.[24] This method is essential for preparing half-reactions that can be combined to form complete redox equations, aiding in the prediction of cell potentials in electrochemical cells.[25] The procedure consists of four main steps:- Balance all elements except oxygen and hydrogen: Adjust coefficients to equalize the number of atoms for all species other than O and H on both sides of the half-reaction equation.[24]
- Balance oxygen using H₂O: Add water molecules to the side deficient in oxygen atoms to achieve equality.[24]
- Balance hydrogen using H⁺: Add hydrogen ions to the side deficient in hydrogen atoms, leveraging the acidic environment.[24]
- Balance charge by adding e⁻: Calculate the total charge on each side and add electrons to the more positive side (for reductions, electrons are reactants; for oxidations, products) to equalize charges.[24]
- Step 1: Manganese is already balanced (1 on each side).
- Step 2: Add 4 H₂O to the right to balance the 4 oxygen atoms on the left.
- Step 3: Add 8 H⁺ to the left to balance the 8 hydrogen atoms from the 4 H₂O.
- Step 4: The left side now has a charge of +7 (from MnO₄⁻ and 8 H⁺), while the right has +2; add 5 e⁻ to the left to balance the charge.
